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Given the function f(x)=-8x+1, find f^-1(-15).
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You need the inverse function or f(x) Do you know how to do this?
@ybarrap would that be f^-1(Y) = (y - 1) / -8 ?
y=-8x+1 exchange x and y x=-8y+1 solve for y 8y=1-x y=(1-x)/8 This is the inverse of f(x) $$ f^{-1}(x)=\cfrac{1-x}{8} $$ Now just plug-in x=-15; $$ f^{-1}(-15)=\cfrac{1-(-15)}{8} $$ Make sense?
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