Question

the equation tan^x+1=sec^x

Answer 1

true or false?

Answer 2

do you mean \[\tan^2(x)+1=\sec^{2}(x)\] ?

Answer 3

tan squared right ??
not tan^x

Answer 4

if yes then rewrite tan in terms of cos sin
reciprocals : \[\tan \theta =\frac{\sin \theta}{\cos \theta}~~~~~\sin \theta=\frac{1}{\csc \theta}~~~~~~\cos \theta=\frac{1}{\sec \theta}\]
the reciprocal of tan theta =1/cot theta
in terms of sin cos you can write it as sin/cos which is same as 1/cot

Answer 5

yes it is squared. I got false am icorrect?

Answer 6

@nnesha????

Answer 7

as given above by @Nnesha tan^2(x) + 1 = sec^2(x)

Answer 8

it is true
use that sin^2 + cos^2 = 1 and tan = sin/cos

Answer 9

copy these down n ur notebook
http://www.purplemath.com/modules/idents.htm
identities

Answer 10

tan theta =sin theta/ cos \[\rm \frac{ \sin^2 \theta}{ \cos^2 \theta}+1 =\sec^2 theta \]
solve left side
find common denominator
\[\frac{ \sin^2 \theta +\cos^2 \theta }{ \cos^2 \theta } =\sec^2 \theta \]
now use the special identity and the fact `1/cosx=secx`