Question

Can someone tell me the problem below is right ?

Answer 1

\[(\sqrt{-25})^{2} -\sqrt{-121} = 625-11 which equals 614\]

Answer 2

nope

Answer 3

square root of negative numbers do not exist

Answer 4

oh okay

Answer 5

lol sure they do

Answer 6

they are 'imaginary'

Answer 7

vocaloid u were right...

Answer 8

so it would be 625i - 11i ?

Answer 9

what happens when a square root is multiplied to a square root...

Answer 10

i dont know

Answer 11

what is \[\sqrt{25}\]

Answer 12

5

Answer 13

have you learnt imaginary numbers?

Answer 14

I started the lesson yesterday

Answer 15

so yea I kind of know about them

Answer 16

what is
\[\sqrt{25\times25}\]

Answer 17

625

Answer 18

what is \[25 \times25\]

Answer 19

625

Answer 20

how can \[\sqrt{25\times25}=625 \\and\\25\times25=625\]
??

Answer 21

for the square root it would equal 25 ? and then 25*25 = 625

Answer 22

yes
\[\sqrt{25 \times 25}=25\\25\times25=625\]

Answer 23

okay

Answer 24

whats an imaginary number?

Answer 25

An imaginary number is a complex number that can be written like a eal number for example i

Answer 26

real*

Answer 27

what is 'i'

Answer 28

i^2 = -1

Answer 29

its an imaginary number which you can turn into a real number

Answer 30

thats right :)

Answer 31

:D

Answer 32

so whats
\[\sqrt{625}\]

Answer 33

25

Answer 34

whats
\[\sqrt{-625}\]

Answer 35

25i ?

Answer 36

thats right :)

Answer 37

really?

Answer 38

\[\sqrt{-625}=\sqrt{-1\times25^2}=\sqrt{-1}\times\sqrt{25^2}=i 25\]

Answer 39

ohh okayy

Answer 40

whats
\[\sqrt{-25}\]

Answer 41

i5

Answer 42

yep :)

Answer 43

so the quotient of two complex numbers is always true ?

Answer 44

i'm sorry i didnt understand what you mean...give me an example

Answer 45

so if a negative is in the square root we always have to put the i ?

Answer 46

inside the square root*

Answer 47

yes you do

Answer 48

okay so \[\sqrt{-121} = i11\]

Answer 49

yes

Answer 50

so it would be \[i25-i11\]

Answer 51

you for got the 'squares'
\[(5i)^2-(11i)^2\]

Answer 52

oh yea

Answer 53

and its 5 not 25

Answer 54

oh alright thank you so much

Answer 55

I understand this a lot better now :D

Answer 56

you know that i^2=-1

Answer 57

yes

Answer 58

so whats
\[(5i)^2\]

Answer 59

would it be -i

Answer 60

hint
\[(5i)^2=5^2\times i^2\]

Answer 61

no

Answer 62

try using my hint

Answer 63

ok

Answer 64

since i^2 equals -1 it can be 5^2*-1 ?

Answer 65

yes

Answer 66

whats 5^2*-1

Answer 67

and that would be -25 because 5^2 is 25 times -1 is -25

Answer 68

correct!!

Answer 69

yay :D

Answer 70

now try (11i)^2

Answer 71

oh..never mind. your question does not ask for it

Answer 72

so..you have done all the necessary calculations to give the final answer to your question.
can you give it?

Answer 73

okay so it would be -25-(11i)^2 ?

Answer 74

it would be
-25 -11i

Answer 75

where did you get ^2 from?

Answer 76

when you said now try (11i)^2

Answer 77

that was my mistake, your question does not ask us to find (11i)^2
it just asks \[\sqrt{-121}\]

Answer 78

oh okay

Answer 79

so then yea it would be 11i

Answer 80

so you understand how we got -25-11i

Answer 81

?

Answer 82

yes thank you

Answer 83

:)