Fill in the blank with a digit such that the resulting number is divisible by 11. (a) 962,974,__34 (b) 92,818,__21 (c) 57,13__,473
Does it mean the number following will be able to be divided by 11?
what do you suppose the answer is?
@markchernioglo I will watch you do this, because I think I know the answer, but not too sure.. :p
lol same but ill try
I believe I know what it is..
so i think A. could be eliminated becuase 962,974 is not a factor of 11.
(a) 962,974,__34 When divided by 11, we don't get a whole number. (b) 92,818,__21 When divided by 11, we don't get a whole number. (c) 57,13__,473 When divided by 11, we get 43.
yup maddie you got it.
that is correct
for the question its asking to find the missing blank number
@markchernioglo I took the thunder, you were starting tho.
:)
to make it true for it to be divided by 11
It is the last one, the number must be 43. Right @markchernioglo
yup
correct
Thought so. :-)
C is your correct answer @Jackiemelbs
yup
If you want to go the extra mile, the answer you get from dividing that by 11 should be the fill in the blank spot.
well igtg if anyone needs help maddy you are smart :)
its not asking for which one is correct, for each letter it wants you to put the 1 missing number to make it true that the number can be divided by 11
@markchernioglo trust me you are uber smart too!! You were right there with me :-) I will fan you!
lol same
So whatever you get from dividing by 11, they want in there?
Or that the answer is divisable by 11?
no its something with some sort of divisibility rule of 11 that we have to use in order to find it and thats why i posted cause i get stuck on it
Ah okay. One second (-: Sorry, I misinterpretted.
Does it request any special numbers, is there a rule to these numbers in the sequence?
Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2-7+2-8 = -11. (I've tried using this but I can never get it to work)
i guess what i don't understand is how to determine this if you are missing a number
Well, I understand that. But, you could honestly put in any numbers. There must be a catch,
Fill in the blank with a digit such that the resulting number is divisible by 11 (a) 962,974,__34 (b) 92,818,__21 (c) 57,13__,473 What I think is they want us to add up all the numbers up until the point of the blank spot possibly
Like for C, 5+7+1+3=16, but see that is not divisible by 11..
and 57 + 13 = 70 which is not divisible by 11, either.
right....ugh this problem sucks haha
It does! I mean, I understand the rule. But there is a trick within these numbers.
And there is no pattern, the numbers are inconsistent.
right....oh well i guess I'll just ask my professor cause i honestly have no idea
Its gotta do with the numbers, if they were in sequence, it would seem more reasonable, but the numbers fluctuate a lot. So, that doesn't help. you could pick any number under these circumstances, for it to be divisble by '11', unless there was something in your lesson that went over these.
Well I have one proposition
We could take each end number, such as a) for 34, times it by 11, giving us 374, putting that into the blank spot.
That is a multiply of 11, and dividing it by 11 yields 34.
b) 21 x 11 = 231. 231 is a factor of 11, so it could be a possible answer.
And mybe put in 43 for c, because that multiplies out to give us 473.
So, A) 374 B) 231 c)43 ( maybe )
do u know the divisibility test for 11
@imqwerty am I somewhat right? Haha
wait a sec ima see :) i ddin't read anything i jst cmnted cx
Haha okay XD
what digits are u filling in the 1st one? i dun get it u wrote 374 but there are only 2 spaces
A) 374 B) 231 c)43 Are my answers
I disregarded the spaces, I think it was just spaces to be space
I highly doubt c is 5203. That seems to be too large.
However, if you divide 473 x 11 = 5203. Which then divided by 11 yields 473, so, that is a possibility.
multiply, not divide..
A) 374 B) 231 c)43 or 5203.
a) 0 b) 1 c) 4 Works: a) 9 -6 + 2 - 9 + 7- 4 + x - 3 + 4 = closest number divisible by 11 0 + x = closest number divisible by 11, in this case it is 0 0 + x = 0, x = 0 b) 9 - 2 + 8 - 1 + 8 - x +2 -1 = closest number divisible by 11 23 - x = closest number divisible by 11, in this case it is 22 23 - x = 22, x = 1 c) 5 - 7 + 1 - 3 + x - 4 + 7 - 3 = closest number divisible by 11 -4 + x = closest number divisible by 11, in this case it's 0 -4 + x = 0, x = 4
(a) 962,974,034 (b) 92,818,121 (c) 57,134,473
Refer to the attached Mathematica calculation.
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