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Linear Algebra 19 Online
OpenStudy (anonymous):

Let L be the line with parametric equations x = −2+3t y = −4−2t z = −4+3t Find the shortest distance d from the point P0=(5, −1, 3) to L, and the point Q on L that is closest to P0.

OpenStudy (fibonaccichick666):

what have you tried?

OpenStudy (anonymous):

i honestly have no idea where to start...

OpenStudy (fibonaccichick666):

so you know the distance formula?

OpenStudy (anonymous):

no

OpenStudy (fibonaccichick666):

you're kidding? this is a calculus problem...

OpenStudy (anonymous):

linear algebra

OpenStudy (fibonaccichick666):

I'm sorry, I don't know how to help you then.

OpenStudy (anonymous):

okay thanks anyways

OpenStudy (fibonaccichick666):

The only way I know how to do this involves derivatives. From a quick google, that appears to be the way of choice for most

OpenStudy (anonymous):

oh but this isn't calculus

OpenStudy (fibonaccichick666):

although, a different approach is taken in the comments here http://math.stackexchange.com/questions/1020562/distance-between-point-and-line-and-between-line-and-plane

OpenStudy (fibonaccichick666):

there apparently is a vector approach

OpenStudy (anonymous):

thanks im going to take a look rn

OpenStudy (anonymous):

i'm still not sure how i should start

OpenStudy (fibonaccichick666):

oh, here ya go. LA solution, I apologize my LA sucks, so I won't be help but try @zepdrix . He may have some ideas: http://math.mit.edu/~gs/linearalgebra/ila0403.pdf

OpenStudy (mathmate):

@michael.sadowski Are yuo still there?

OpenStudy (mathmate):

Here's a link that solves a similar problem as yours. If you need further help, just post/tag me, or @FibonacciChick666. http://math.stackexchange.com/questions/371649/distance-of-a-3d-point-from-the-parametric-form-of-a-line

OpenStudy (anonymous):

oh hey i ended up figuring it out, but i have another question

OpenStudy (mathmate):

I suggest you post a new question and tag someone if you wish. However, there are always others interested online.

OpenStudy (denisaboichuk):

no

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