How can I calculate the velocity at the top of a golf ball with known values for angular velocity and the speed through the centre of mass (vG)? Diagram is below:

Question

anonymous · Answer

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anonymous · Answer

Any help would be great!!

anonymous · Answer

Problem in entirety is:
A golf ball is struck a mighty blow from a driver, lauching it at an angle of θ=10.1o.

The golf ball has been constructed to current professional standards for mass and size:

mB=45.9g and RB=21.5mm.

The impact between the club and the ball may be crudely modelled as a uniform (average) force of F=43kN for a duration Δt=43 μs through a line of action such that b=3.27mm.

Hint: You may assume the impact is sufficiently brief that the ball does not change orientation during the impact.
(vG=40.28 and w=712.4 (angular velocity))
a)What is the magnitude of the velocity of the point A ( vA), on top of the ball, immediately after impact?

anonymous · Answer

@IrishBoy123, it would be a massive favor if you could please assist me with my problem. I have been trying various means and can't find the solution. It seems simple and yet I can't solve it. No one else has replied

irishboy123 · Answer

if you have made the other two calcuations, which i find to be correct, then you are left with this very easy one.  the top of the ball is travelling with the ball obviously, but it is spinning "backwards" so its speed is simply $v_B - R_b \omega_b$

anonymous · Answer

Thanks a lot, knew it would end up quite simple. Just couldn't see it.