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OpenStudy (shaleiah):

Quadratic formula (Medal) (Fan)

OpenStudy (shaleiah):

+16** not 6

OpenStudy (shaleiah):

@tanya123

OpenStudy (shaleiah):

the values of a,b,c

OpenStudy (anonymous):

`Quadratic Formula`: \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] Note that c will be -5 when we move the 11 over to the other side. P lug in your values and solve carefully :) Let me know if you get stuck

OpenStudy (anonymous):

5* not -5

OpenStudy (shaleiah):

\[\frac{ -3\pm \sqrt{-3^2-4(5)(-5)} }{ 2(5) }\]

OpenStudy (anonymous):

It should be 4(5)(5), but yes, that is correct so far. Make sure that when you evaluate -3^2, you evaluate it as (-3)^2 so that the negative is inside the square. :) Continue to simplify it and let me know what you get

OpenStudy (anonymous):

Oh and there should be a positive 3 in front, sorry. Because you have -b but b = -3, so -(-3)=3

OpenStudy (shaleiah):

\[\frac{ 3\pm \sqrt{109} }{ 10 }\]

OpenStudy (anonymous):

I believe it should be -91 on the inside. \[\frac{3 \pm \sqrt{(-3)^2-4(5)(5)}}{10} = \frac{3 \pm \sqrt{9-100}}{10}\]

OpenStudy (triciaal):

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