Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shaleiah):
+16** not 6
OpenStudy (shaleiah):
@tanya123
OpenStudy (shaleiah):
the values of a,b,c
OpenStudy (anonymous):
`Quadratic Formula`:
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
Note that c will be -5 when we move the 11 over to the other side. P lug in your values and solve carefully :) Let me know if you get stuck
OpenStudy (anonymous):
5* not -5
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shaleiah):
\[\frac{ -3\pm \sqrt{-3^2-4(5)(-5)} }{ 2(5) }\]
OpenStudy (anonymous):
It should be 4(5)(5), but yes, that is correct so far. Make sure that when you evaluate -3^2, you evaluate it as (-3)^2 so that the negative is inside the square. :) Continue to simplify it and let me know what you get
OpenStudy (anonymous):
Oh and there should be a positive 3 in front, sorry. Because you have -b but b = -3, so -(-3)=3
OpenStudy (shaleiah):
\[\frac{ 3\pm \sqrt{109} }{ 10 }\]
OpenStudy (anonymous):
I believe it should be -91 on the inside.
\[\frac{3 \pm \sqrt{(-3)^2-4(5)(5)}}{10} = \frac{3 \pm \sqrt{9-100}}{10}\]
Still Need Help?
Join the QuestionCove community and study together with friends!