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b2(p + 3) + q(p + 3) In factored form... I'm still working on it the way she taught me...
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\(ab+ac=a(b+c)\)
that absolutely does nothing to help me. I don't understand why but I think the answer is (b^2*p)(q+3)
b^2(p + 3) + q(p + 3) - Factoring by Grouping The terms b^2 *(p + 3) and q*(p + 3) have a common factor of (p + 3).
That wasn't the right answer.
Factor out (p+3) in this way: b^2 *(p + 3) and q*(p + 3) = (p + 3)* ( b^2 + q)
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By the commutative property, that answer can also be written as: (b^2 + q) ( p + 3)
I was talking about my guess.
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