A company is creating three new divisions in three different countries. Seven managers are eligible to be appointed head of a division. How many different ordered ways could the three new heads be appointed?

Question

anonymous · Answer

For this one, I ran a combin again.. but Im not sure..
combin (7,3) = 35

Im not sure if there is actually more to this.

anonymous · Answer

is it actually a total of 9 divisions?

hartnn · Answer

no, only 3 divisions,
one division per country 

choose 3 managers from 7,
combin(7,3) is correct :)

anonymous · Answer

THANKS again !

hartnn · Answer

wait, does the order matter here?

anonymous · Answer

ah I dont think so...

anonymous · Answer

I did think about that..

anonymous · Answer

so I should always ask that I suppose.

rvc · Answer

no i dont think order matters

hartnn · Answer

A in country 1 , B in country 2, C in country 3

B in country 1, A in country 2 , C in country 3 

these both are different, right?????

rvc · Answer

nope order doesnt matter in this case

anonymous · Answer

Well I do have another question similar..
"Suppose 15 students are lined up outside a classroom waiting to get in. You want to determine how many different ordered ways they can enter the classroom, one at a time. Check all of the correct methods you could use to determine how many different ordered ways they can enter the classroom."
This looks like order matters.,

anonymous · Answer

or wait.. it does ask.. "how many different ordered ways"

anonymous · Answer

so order does matter hey.

hartnn · Answer

exactly my point

ABC, BCA, ACB, BAC.... are all different

rvc · Answer

hmm
read the question twice

anonymous · Answer

ok, so it's 210 .. permut(7,3)

hartnn · Answer

correct

rvc · Answer

They just want the numbers of ways
order is not mentioned

anonymous · Answer

are you sure RVC? 
Quote "How many different ordered ways could the three new heads be appointed?"

hartnn · Answer

for the 2nd one, yes order matters.
so toal how many ways?

anonymous · Answer

are there other methods other than permutation to find how many different ordered ways? or permutation the only way? say given multiplication rule, or factorials.. and combos.

anonymous · Answer

this looks like a factorial would also give us an answer.. being that they are ALL going in.

hartnn · Answer

correct

rvc · Answer

15 students can enter in 15different ways

anonymous · Answer

it looks like 15! would give us the answer too

rvc · Answer

correct :)

hartnn · Answer

15! is correct. 

paermuation is just one of the many ways.

like you can use permutation for 2nd problem,
permute (15,15) = 15!

rvc · Answer

all d best :)

anonymous · Answer

thanks guys.. I think I'm good then.