What is the simplified form of 4 sqrt x^2 times 4 sqrt x^2? ( i think it looks like 4√ײ times 4√ײ ) the answer choices are x^1/2 x x^2 √x
Need help
First Tengo que ir a caca .
is it \[\huge\rm \sqrt[4]{x^2} * \sqrt[4]{x^2}\] 4 as an index ?
yes thats it! i couldn't find the thing to do that
alright apply the exponent rule you can convert radical to an exponent form \[\huge\rm \sqrt[\color{Red}{n}]{x^\color{blue}{m}}=x^\frac{\color{blue}{ m }}{ \color{ReD}{n} }\]index becomes denominator of fraction
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so it's x^2/4 ?
yes convert both radical to an exponent fform \[\huge\rm x^\frac{ 2 }{ 4 }*x^\frac{2}{4}\]
and when we multiply same bases we should `add` exponents \[\huge\rm x^m \times x^n=x^{m+n}\]
so it's 3x?
I don't understand
how did you get 3 ?
because 2+2 is 4 and 4 over 4 is 1 there are 2 x's so 3x? idk i'm bad at math
alright first we converted radical to an exponent form right \[\huge\rm \color{ReD}{ \sqrt[4]{x^2}} * \color{blue}{\sqrt[4]{x^2}}\] \[\huge\rm\color{Red}{x^\frac{ 2 }{ 4 }}*\color{blue}{x^\frac{2}{4}}\] you can reduce the fraction first 2/4 and then add the exponents
here is an example \[\huge\rm x^4 *x^4 =x^{4+4}=x^{8}\] we end up with only one base
x^8 is shorthand forx^4 * x^4
so when we combine them we should write it in terms of single base \[\huge\rm\color{Red}{x^\frac{ 2 }{ 4 }}*\color{blue}{x^\frac{2}{4}}\] \[\huge\rm x^{\frac{2}{4}+\frac{2}{4}}\]
so it's x^2 ?
hmm how did you get 2 ?
\(\color{blue}{\text{Originally Posted by}}\) @madmerc because 2+2 is 4 and 4 over 4 is 1 there are 2 x's so 3x? idk i'm bad at math \(\color{blue}{\text{End of Quote}}\) right 2+2 = 4 and 4/4 =1 that's correct but there is only one x
so is it just x as the answer?
right which is same as x^1
thank you so much
np :=))
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