Question

Ψ(x,t)
=Ax/a, if 0<=x<=b , =A(b-x)/(b-a), if a <=x<=b, =0, otherwise, whr a,b are constant...1.sketch
Ψ(x,0)
as a fuction of x

Answer 1

Do you understand how i got the sketch?

Answer 2

NB: I am assuming a \(\color{brown}{\textit{typo}}\)
\[\Psi(x,t) = \begin{cases}
A\dfrac xa & \text{if }0\leq x\leq \color{brown}a,\\[2ex]
A\dfrac{b-x}{b-a}& \text{if }a \leq x\leq b,\\[2ex]
0& \text{otherwise.}
\end{cases}\]

Answer 3

no....i didnt got..
plz explain me...

Answer 4

sry..bt i aslo tried to type like ur s equation bt i couldnt do tht...

Answer 5

lets look at the 0≤x≤a domain first

Ψ(x,0) = A x/a

This is the equation of a straight line thought the origin.

for x = 0 , Ψ = 0, i.e. (0,0)
for x = a , Ψ = A i.e. (a,A)

Answer 6

Now lets look at the a≤x≤b domain

Ψ(x,0) = A (b-x)/(b-a)

This is also the equation of a straight line

for x = a , Ψ = A, i.e. (a,A) (as before)
for x = b , Ψ = 0 i.e. (b,0)