Question

"Finding Quadratic functions" question! Need help with second part.

Answer 1

Find two quadratic equations of x which are zero at x=1 , which take the value 10 when x =0 , and which have a maximum value of 18.

Answer 2

I figured out that the first answer is:

\[-2x^2 - 8x +10\] , but I'm having trouble finding the second equation.

Answer 3

since at x=1 it is zero so x-1 is factor of both eq.s .

Answer 4

I used \[ax^2 +bx +10\] as my " base equation" , used \[f(-b/2a) = \min/or/\max/point/\]

Came up with:

b= - 8 or (6+2/3)

I can't take the second value of b and come up with the right answer. :c

Answer 5

@Er.Mohd.AMIR

Ah! That's an interesting idea...

Answer 6

so (a-b) should always equal -10 , hmm.

Answer 7

a+b=-10

Answer 8

ax^2+bx+c=0 and x=1 give zero

Answer 9

C will always be 10, I think.

Answer 10

otherwise, it could never = 10 when x = 0.

Answer 11

c is equal to 10 and a+b+c=0 gives a+b=-c
a+b=-10

Answer 12

use your method, you can also use the other root from the quadratic formula

Answer 13

\[b=\dfrac{32 \pm \sqrt{32^2 + 4(320)} }{2}\]