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Is there anything wrong with this work? cosθ/2 = √((1 + cosθ)/2) cosθ = 24/25 cosθ/2 = √(1 + (24/25)/2 cosθ/2 = √((49/25)/2) cosθ/2 = 7/√50
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Then you can optionally rationalize the denominator by multiplying top and bottom by \(\Large \sqrt{50}\)
Keep in mind that \[\Large \sqrt{50} = \sqrt{25*2} = \sqrt{25}*\sqrt{2} = 5\sqrt{2}\]
Nothing else is wrong with it?
Because my teacher didn't give me credit for it
if you rationalize the denominator and use the fact that \[\Large \sqrt{50}=5\sqrt{2}\] then you should get \[\Large \cos\left(\frac{\theta}{2}\right) = \frac{7\sqrt{2}}{10}\]
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Ok...thanks!
no problem
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