Ask your own question, for FREE!
Calculus1 27 Online
OpenStudy (revircs):

Need help with an inverse function:

OpenStudy (revircs):

OpenStudy (revircs):

Let k(x) = (f(x))^−1. what is k'(2)?

OpenStudy (revircs):

I had the answer as -.12, but I dont remember how I got it.

OpenStudy (princeharryyy):

is it f(x) to the power -1

OpenStudy (revircs):

\[(f(x))^-1\] like this

OpenStudy (revircs):

so yeah, (f(x)) to the power of -1

OpenStudy (princeharryyy):

ok

OpenStudy (princeharryyy):

what's that apostrophe on k(2) is it the differentiation.

OpenStudy (revircs):

yes

OpenStudy (princeharryyy):

are you sure, you got the right answer.

OpenStudy (revircs):

Yeah, it marked it as correct for me

OpenStudy (princeharryyy):

See, from the information given you can not find f(x). Now, if that you can't do. You can not find the k(x). And, if it's not possible to find k(x) how can you find differentiation of k(x).

OpenStudy (revircs):

@baru any idea?

OpenStudy (princeharryyy):

from the information we only know that f(2) =5 and that if it is f(x) to the power -1 => k(2) = (5)^-1.

OpenStudy (revircs):

I found it out, we take the derivative of both sides. so k'(x) = -f(x)^(-2) * (f'(x))

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!