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Mathematics 15 Online
OpenStudy (anonymous):

thanks:)

Directrix (directrix):

The answers lie in the slopes of the two lines. The first task is to get the slopes of the two lines.

Directrix (directrix):

2x+ky =3 ky = -3 - 2x ky = -2x - 3 y = -2x/k - 3/k y = (-2/k) * x - 3/k Slope is -2/k and x+y=1 y = -1x + 1 Slope is -1

Directrix (directrix):

Parallel lines have the same slope. That means that: (-2/k) = -1 Solve for k @cutegirl Post what you get, okay?

OpenStudy (anonymous):

2?

Directrix (directrix):

Yes, that is what I got but I need to check it.

Directrix (directrix):

@Jadedry Would you like to help with the part b about the value of k which would make the lines perpendicular?

OpenStudy (jadedry):

For (b) the lines have to be perpendicular , in order that they're perpendicular, their slopes have to be negative reciprocals of each other. 2x+ky=3 and x+y=1 Lets simplify: /2x+ky = 3 / ky = 3-2x y = 3-2x/k /x+y = 1/ y = 1-x (Remember slope is the coefficient of the x!) the coefficient of x in y = 1-x is -1 You have to find a value of k in y = 3-2x/k such that the coefficient of x becomes the negative reciprocal of -1. Can you figure it out?

OpenStudy (anonymous):

-2?

OpenStudy (jadedry):

Correct! c:

Directrix (directrix):

It is more fun to work together!

OpenStudy (jadedry):

Yup! c:

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