Identify the vertex, axis of symmetry, maximum or minimum, and domain and range of the function. F(x)=2(x+9)^2-4
What have you done so far?
I don't understan any of it...
well the vertex form of the parabola is \[y = a(x - h)^2 + k\] (h, k) is the vertex... so what is the vertex in your equation... just match the information
(9,4)
close your equation is \[y = 2(x - (-9))^2 + (-4)\] this may make it easier.... you need to check
So (-9,-4)
great... next, the line of symmetry is the h value in the vertex... and it will be in the form x = ..? any thoughts...
or to make it easier... the line of symmetry is the x value in the vertex
So -9^2?
you need the values from the vertex... you said the vertex is (-9, -4) so the line of symmetry comes from the vertex and is x = -9 does that make sense...?
Oh okay yeah
the max or min value also comes from the vertex.. in your question, the parabola is concave up... so the minimum value is the y-value in the vertex... so what do you think the minimum is y = ??
y=-4
that's correct... the curve looks like this |dw:1446578016113:dw|
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