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Algebra 14 Online
OpenStudy (pagen13):

Identify the vertex, axis of symmetry, maximum or minimum, and domain and range of the function. F(x)=2(x+9)^2-4

OpenStudy (jchick):

What have you done so far?

OpenStudy (pagen13):

I don't understan any of it...

OpenStudy (campbell_st):

well the vertex form of the parabola is \[y = a(x - h)^2 + k\] (h, k) is the vertex... so what is the vertex in your equation... just match the information

OpenStudy (pagen13):

(9,4)

OpenStudy (campbell_st):

close your equation is \[y = 2(x - (-9))^2 + (-4)\] this may make it easier.... you need to check

OpenStudy (pagen13):

So (-9,-4)

OpenStudy (campbell_st):

great... next, the line of symmetry is the h value in the vertex... and it will be in the form x = ..? any thoughts...

OpenStudy (campbell_st):

or to make it easier... the line of symmetry is the x value in the vertex

OpenStudy (pagen13):

So -9^2?

OpenStudy (campbell_st):

you need the values from the vertex... you said the vertex is (-9, -4) so the line of symmetry comes from the vertex and is x = -9 does that make sense...?

OpenStudy (pagen13):

Oh okay yeah

OpenStudy (campbell_st):

the max or min value also comes from the vertex.. in your question, the parabola is concave up... so the minimum value is the y-value in the vertex... so what do you think the minimum is y = ??

OpenStudy (pagen13):

y=-4

OpenStudy (campbell_st):

that's correct... the curve looks like this |dw:1446578016113:dw|

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