Did I rounded off to the CORRECT SIGNIFICANT DIGITS???

Question

gabbyalicorn · Answer

Let's see. Did you?

fanduekisses · Answer

$$0.400 g Mg \times \frac{ 1 mol  }{ 24.31 g Mg }\times \frac{ 2 mol MgO }{ 2 mol Mg }\times \frac{ 40.31 g MgO }{ 1 mol MgO }$$

gabbyalicorn · Answer

oh my. o-0 i thought it was like baby rounding. My bad. xD

fanduekisses · Answer

0.663266146

fanduekisses · Answer

I will have to round off to one significant digit right?

fanduekisses · Answer

@amistre64

fanduekisses · Answer

@surjithayer

amistre64 · Answer

i never really did get the hang of sig-digits ...

anonymous · Answer

yes you did it right @Fanduekisses

fanduekisses · Answer

so it will be 0.7 grams?

fanduekisses · Answer

Idk if its one or three sig figs.

fanduekisses · Answer

@campbell_st

anonymous · Answer

yes it woul @Fanduekisses

lanhikari22 · Answer

http://www.sigfigscalculator.com/ Use this to get the rules down, it's helpful.

lanhikari22 · Answer

Basically when adding, you don't go beyond the decimal places of the lesser.
When multiplying, you don't go beyond the total significant figures of the lesser.
Ex: 999 * 0.99 = 990
0 BEFORE the decimal doesn't count as precision, but it does, after the decimal.
So, 990. is NOT the same as 990, because 990. assumes that 0, is not significant.

lanhikari22 · Answer

I'm sorry, I mean 990. assumed 0 IS significant while 990 does not.

lanhikari22 · Answer

990. (3 Significant Figures)
990 ( 2 Significant Figures, lines up well with 999 * 0.99 because 3 * 2 = 2)