Question

Secx+cscx=1
Prove the identity
Will give medal

Answer 1

let's take left hand side and prove that it is actually 1.

so left h side is
Secx+cscx

and multiply it by sinX.. so we get
tanX + 1

Answer 2

Are you sure this question is correct?

Answer 3

your question is wrong unfortunately.

Answer 4

Yes it's correct

Answer 5

@Nnesha

Answer 6

what's the reciprocal of sec and csc ?

Answer 7

Cos tan and sin

Answer 8

hmm sec = 1/cos
not just cos
and csc = 1/sin

Answer 9

Srry I wrote it wrong

Answer 10

\[\frac{ 1 }{ \sin x } +\frac{1}{\cos x} =1\]
now find common denominator

Answer 11

or you can do the other way like lochana mentioned
but when we prove identity we should work only one side (most of the case where we only work on one side )

Answer 12

on*

Answer 13

So work on the left side

Answer 14

@Nnesha yes. You are correct. But I don't think you can make it. because the only way that secx+ cscx =1 when x = 0

Answer 15

correct \[secx +\csc x \cancel{ =}1\]

Answer 16

multiply by sin(we should multiply *both* sides by sin)\[\rm sinx(\frac{ 1 }{ \sin x } +\frac{1}{\cos x}) =1*sinx\]

sorry i meant to say multiply by sin

Answer 17

I multiply by tan

Answer 18

distribute parentheses by sin

Answer 19

by sin** not tan sorry that was a mistake

Answer 20

Cscx

Answer 21

what about it ??

Answer 22

Is that what it equals

Answer 23

hmm no distribute parentheses by sin x
\[\rm \color{Red}{sinx}(\frac{ 1 }{ \sin x } +\frac{1}{\cos x}) =1*sinx\]

\[\rm \color{red}{sinx}*\frac{1}{sinx}+\color{ReD}{sinx}*\frac{1}{cosx}\]
simplify left side

Answer 24

1+tan

Answer 25

yes right that's how lochana got tanx+1 at left side \[\rm tanx+1=sinx\] both sides aren't equal

Answer 26

Oh okay so my question wouldn't be an identity because they don't equal

Answer 27

@bluenile955 you are correct. you end up with getting 1+ tanx . which is only give you 1 when x = 0 .

Answer 28

Thx