Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Anyone know how to solve this?

OpenStudy (anonymous):

OpenStudy (anonymous):

fint the volume of the cylinder and the cone and add they together

OpenStudy (anonymous):

find*

OpenStudy (anonymous):

tagg me if you need further help

OpenStudy (anonymous):

\[\huge V_{total}=V_{cylinder}+V_{cone}\]

OpenStudy (anonymous):

\[Cynlinder = \pi r^2 h \] \[cone = \frac{ 1 }{ 3 } \pi r^2h\]

OpenStudy (anonymous):

367.56 isnt an answer?

OpenStudy (anonymous):

give me a sec ill walk you through this :) @LegendaryNikki

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

okay so what is the formula for the volume of a cone? :D

OpenStudy (anonymous):

V=πr2h/3

OpenStudy (anonymous):

sorry my wifi is slow today haha but calculate the volume of the cone when: r=3 h=9

OpenStudy (anonymous):

84.82

OpenStudy (anonymous):

roughly haha so now we find the volume of the cone with: r=3 h=10

OpenStudy (anonymous):

282.74

OpenStudy (anonymous):

ignore, doesn't ask for the pi

OpenStudy (anonymous):

okay so we add the volumes together

OpenStudy (anonymous):

367.56

OpenStudy (anonymous):

r^2*h r^2*h/3

OpenStudy (anonymous):

oh hes got it xD didnt see the answer sorry lmao

OpenStudy (anonymous):

andres is correct my bad

OpenStudy (anonymous):

i dont get whats the answer

OpenStudy (anonymous):

okay so we plug in the terms and simplify so the answer will look like: V=___pi^3

OpenStudy (anonymous):

you don't need to use pi just this to put it simple \[r^2*h\] for the cylinder \[r^2*\frac{ h }{ 3 } \] for the cone

OpenStudy (anonymous):

90 + 27= 117?

OpenStudy (anonymous):

yes, correct

OpenStudy (anonymous):

Thanks guy

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!