Help!! WIll medal and fan!! Pleaseee help
Suppose an isosceles triangle ABC has A = 45 (degrees) and b=c=3. What is the length of a^2?
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OpenStudy (studytheworld):
@ParthKohli @zepdrix Anyone?
OpenStudy (anonymous):
a=BC^2=9.42
OpenStudy (studytheworld):
Dude that's not even an answer choice, stop telling me false information
OpenStudy (studytheworld):
@Peach-es1234
OpenStudy (anonymous):
What is the answer choices.............
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OpenStudy (ronlover101):
sin A/(BC) =sin C/(4)
BC=sin A/sin C *4= 0.707*4/0.92=3.07
standard ratio of sin to side
OpenStudy (ronlover101):
so a=BC^2=9.42
OpenStudy (studytheworld):
2.30
5.27
30.73
12.73
Do one of those say 9.42? No
OpenStudy (anonymous):
Well how are we suppose to know if that was correct if the answer choices weren't posted.
OpenStudy (trojanpoem):
|dw:1446753684274:dw|
use the cosine law:
a^2 = b^2 + c^2 - 2bc cos A
well, it's asking for a^2 , and you have all the unknowns
a^2 = (3)^2 + (3)^2 - 2 * 3 * 3 * cos45
a^2 = 5.27
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