Question

Please help!! Will medal! helpp
In the following triangle, (theta) = 60. Find the values of the angles B and B', which solve this ambiguous case. (See screenshot)

Answer 1

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Answer 2

@TrojanPoem Can you help me again? I appreciate it so much!

Answer 3

Use the sine law:

12.3 / sin 60 = 13/ sin b

sinb = 13 * sin60 / 12.3
b = 66.25

the small triangle is iso, so

b' = 180 - b

b' = 180 - 66.25 = 113.75

Answer 4

So it's A?

Answer 5

And also can you go over the formula you used to find the solution again?

Answer 6

It's called the sine rule:



For any triangle ABC:

\[\frac{ a }{ \sin(A) } = \frac{ b }{ \sin(B)} = \frac{ c }{ \sin(C) } = 2r\]

Answer 7

r is the radius of the circle passing through the heads of the triangle.

Answer 8

Ohhh yes. I get it

Answer 9

Thanks for help :)

Answer 10

You're always welcome.