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Use the Pythagorean Theorem to solve for the hypotenuse in the right triangle: leg = 6, leg = 8, hypotenuse =
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|dw:1446758734797:dw| hypotenuse^2 = leg^2 + leg^2 hyp = sqrt( 8^2 + 8^2 = 8sqrt(2)
|dw:1446758921266:dw|
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CY BOOM
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so - how about using th epythagoras equation as required you know th e two smaller sides and you know (from pythaogoras) that H^2 = 6^2 +8^2 so work out H
or maybe you could recognise the special case of a "3,4,5" triangle here?
@terry1234566 , M4D ?
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