Question

Solve: Question 1: 3(5)^2x-3=6 Question 2: 2^x-4+10=22 Question 3: log_3 3+log_3 x=5.

Answer 1

so in the 1st question divide both sides of the equation by 3

and you get

\[5^{2x - 3} = 2\]

now take the log of both sides... base e or base 10

\[\ln(5^{2x -3}) = \ln(2)\]

apply the log law for powers

\[(2x -3)\ln(5) = \ln(2)\]

now you should be able to solve for x.