Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
I got 5 for one of the answers, and I got it down to the quadratic \[(2x ^{3}+5x-3)\] but now Im stuck.
use the quadratic formula
ah, its multiple choice too. the other two factors are +/-3 and +/- (1/2) but I dont know how to find that.
sorry. I meant the other 2 zeros.
Did you read my link? If you follow the same process, you'll get your answers
yeah, but how would I use that system with a fraction?
What are you talking about?
hmm... I need to know how to factor the quadratic I got it down to. Its relatively basic, but its confusing me.
\[\large \text{Quadratic Formula}: \huge x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] If you unsure how to factor a second degree polynomial with 3 terms, always resort to the quadratic formula. The more you do it, the faster you'll get with it, promise.
what does b stand for again?
Correction: It doesn't have to be with 3 terms. Can't be with any amount of terms but a cannot be 0 (or else it wouldn't be a quadratic anymore!) \[\huge y=ax^2+bx+c\]
thanks.
Also, if you're certain that 5 is a solution, there is a theorem that lets you solve the rest of the roots via synthetic division! If you're taking Algebra 2, you will probably learn this (unless you already have). http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-cubicequations-2009-1.pdf Section 3
yeah. thats what this problem is about.
im on the last step.
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