Question

What is the standard form of 3−i2i?

Answer 1

3-i over 2i like a fraction

Answer 2

\[\frac{ 3-i }{ 2i }\]

Answer 3

like this?

Answer 4

standard form is a + bi
conjunct of a + bi = a - bi ( not -a + bi)
to reach that, multiply times the conjunct of the denominator:

3- i /2i

-2i(3-i) / -4i^2

i = sqrt(-1)
i^2 = -1

-6i -2/ 4
-3/2i - 0.5