Question

What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4?

x = −1 and x = −2
x = −1 and x = 2
x = −1 and x = −4
x = 1 and x = −4

Answer 1

@OregonDuck

Answer 2

factor first...

Answer 3

the top is 4x+8 which is 4(x+2)
as long as (x+2) doesn't occur in the denominator then we don't have to worry about holes
and the only thing we will have from the bottom being 0 is vertical asymtpotes
so
factor x^2+3x-4
and set to equal to 0
and solve for x

Answer 4

so what am i setting to 0?

Answer 5

@freckles whereed ya go?

Answer 6

@haleyelizabeth2017

Answer 7

@confluxepic

Answer 8

please i need help

Answer 9

the demonstrator
the x^2+3x-4