Not sure if anyone can help or not..
If the ball shown in the figure lands in 1.0 s, about what height was it thrown from?
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OpenStudy (maddy1251):
OpenStudy (loginusernamed):
15.
OpenStudy (maddy1251):
@Loginusernamed How do you figure out that?
OpenStudy (loginusernamed):
Take a ruler measure the 25M then measure the ?M then figure out.
OpenStudy (maddy1251):
I know this is a physics based question, I wasn't sure if there was a way to do it that way.
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OpenStudy (loginusernamed):
Uhh if D=SxT that distance is 25=_x_?
OpenStudy (mathmate):
Use kinematics equation
\(Y=v_0 t-(1/2)gt^2\)
where \(v_0\)=0 = initial vertical velocity
and g=9.81 m/s^2 = acceleration due to gravity.
OpenStudy (welshfella):
Hmm - Its been a long time but i think you can use the gravity equations to do this:-
height = u + 0.5*g*t^2
u = initial vertical velocity = 0, g = 9.8 m s-3 and t = 1
so h = 4.9* 1^2 = 4.9 m
OpenStudy (welshfella):
* 9.8 m s-2
OpenStudy (maddy1251):
@welshfella I was thinking that it was approx. around 5. BUT I had guessed, I needed to see someone work it out. Much thanks!! :D
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