Not sure if anyone can help or not.. If the ball shown in the figure lands in 1.0 s, about what height was it thrown from?
15.
@Loginusernamed How do you figure out that?
Take a ruler measure the 25M then measure the ?M then figure out.
I know this is a physics based question, I wasn't sure if there was a way to do it that way.
Uhh if D=SxT that distance is 25=_x_?
Use kinematics equation \(Y=v_0 t-(1/2)gt^2\) where \(v_0\)=0 = initial vertical velocity and g=9.81 m/s^2 = acceleration due to gravity.
Hmm - Its been a long time but i think you can use the gravity equations to do this:- height = u + 0.5*g*t^2 u = initial vertical velocity = 0, g = 9.8 m s-3 and t = 1 so h = 4.9* 1^2 = 4.9 m
* 9.8 m s-2
@welshfella I was thinking that it was approx. around 5. BUT I had guessed, I needed to see someone work it out. Much thanks!! :D
yw
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