The sides of a square are three to the power of two sevenths inches long. What is the area of the square?
nine to the power of four sevenths square inches three to the power of four sevenths square inches three to the power of the fraction four over forty nine square inches nine to the power of the fraction four over forty nine square inches
so the side length is \[3^{\frac{2}{7}}\] then the area is \[A = 3^{\frac{2}{7}} \times 3^{\frac{2}{7}}\] so use the indea lat form multiplying the same base.... add the powers \[x^a \times x^b = x^{a + b}\]
Im not good at this can u show me how?
add you need to do is add the fractions... both numbers have 3 as a base
Okay so 3 and 4/14
But there is no answer like that
So how do I find the answer?
no, when you add fractions with the same denominator... just add the tops 5/11 + 2/11 = 7/11 notice the denominator doesn't change
So what will be the answer?
well go back and add the 2 fractions...
thats what I did and it ended up 3 and 4/14
Could u show me how to do it Im really bad at this
here is a link to a fractions calculator... try it http://www.calculatorsoup.com/calculators/math/adding-fractions-calculator.php
or on your calculator 2/7 + 2/7 and see what you get
And?
Im stuck I dont know what to do
just add the numerators... and leave the denominator as 7
4?
so using your idea if you have 1/2 cheese pizza another 1/2 of mushroom pizza you only have 1/4 of a pizza
so 4 over what...?
7
3 and 4 over 7
there you go... that's the answer
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