Find the equation of the line that passes through the points (2, 5) and (2, 12).
start by finding the slope... change in y divided by chaneg in x
a 'mathlete' called 'calculus' - asking about slope intercept equation!!!
If you read my profile then you be clear of this "calculus" misconception.
@MrNood
(2, 5) (2, 12) I know that is an undefined slope but I don't know how to put this as an equation.
OK Do you recognise the 'slope intercept ' form of the linear equation y=mx+b ??
Yes
I got the slope as 0 because \(\large \frac{7}{0} = 0\).
Undefined slopes have the same x value?
that's correct... so what's the equation..?
I got the y-int as 5 because: \(\large 5 = 0(0) + b\) \(\large 5 = 0 + b\) \(\large 5 = b\)
So I guess that the equation should be like: \[\large y = 0x + 5 \] which i believe can equal to \[\large y = 5 \]
On the plane, we can define the "line" as the set of points whose change in y over change in x gives a constant called "slope". This slope is also defined as the angle of the line respective to the x-axis: |dw:1446843634598:dw| so, in orer to calculate this angle, we can use the tangent, so therefore: \[m=tg (\alpha)\] and "slope" is also defined by two points, so we can define two points \(a(x_a,y_a)\) and \(b(x_b,y_b)\) and some play with the intervals, we obtain : \[tg (\alpha) = \frac{ y_b - y_a }{ x_b - x_a }\] So therefore, the slope must be defined by the equation: \[m=\frac{ y_b - y_a }{ x_b - x_a }\]
|dw:1446843910797:dw| what is true about the X value for ALL y values?
just plot the points |dw:1446843978575:dw|
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