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Chemistry 18 Online
OpenStudy (anonymous):

Can someone help with some chemistry?

OpenStudy (anonymous):

http://cvms.canfield.k12.oh.us/homepages/data/canf_cc/files/ap_092313.pdf Can someone help with 3 the first one on the page with the red, blue, and purple circles?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@BAdhi

OpenStudy (anonymous):

@Data_LG2

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

Is the link working for you

OpenStudy (photon336):

The question that says: 2A + B --> C right? If so.. what is your interpretation of this equation?

OpenStudy (photon336):

and secondly, do you know what the limiting reagent is?

OpenStudy (anonymous):

I thought it would be D because I think you have 8 of A and 5 of B. So B is your limiting.

OpenStudy (anonymous):

So the most you could make is 5

OpenStudy (anonymous):

And you would have 3 red/A left over?

OpenStudy (photon336):

Think about this again: in this chemical reaction you need 2 molecules of A for every molecule of B. can you see why?

OpenStudy (photon336):

Let's count them up We have 8 atoms A Red and 5 atoms of B blue right?3

OpenStudy (anonymous):

Right

OpenStudy (photon336):

the chemical reaction says that 2 molecules of A react for every molecule of B

OpenStudy (anonymous):

You wouldn't multiply the 8 by 2 right and get 16?

OpenStudy (photon336):

let's go back first, we know that one of the reactants is going to run out first. 8 atoms of A and 5 atoms of B. 2A + B --> C i'm pretty sure that we need 10 atoms of A to react with 5 atoms of B. but we only have 8 atoms of A reacting with 5 atoms of B. so A will be the limiting reactant and we will be left with 1 atom of B left over BLUE.

OpenStudy (anonymous):

How exactly did you figure that out?

OpenStudy (photon336):

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