Question

2 CO + O2 --> 2 CO2 I need help deciding what would be the limiting reactant and how much CO2 would be created.

Answer 1

think of it this way: if you have equal amounts of CO and O2, which one will you run out of first?

Answer 2

Wouldn't it be CO since it's 2 to 1?

Answer 3

yup, so that's your limiting reactant (assuming that you have equal amounts of each, since you didn't specify)

Answer 4

Sorry 6 CO2 and 3 O2

Answer 5

6 moles of CO2 and 3 moles of O2 as your starting amounts?

Answer 6

Yes. It was on a picture and I forgot to include it.

Answer 7

Are you able to help with just knowing it's 6 CO and 3 O2 as starting amounts?

Answer 8

@Photon336 I think I got myself confused. What I did was
6 molecules CO * (1mol O2/2CO) =3 CO
3 molecules O2 * (2CO/1 O2) = 6 O2

Answer 9

So that means the CO is the limiting right?

Answer 10

And would have 3 extra O2? I feel I messed up somewhere.

Answer 11

I think I figured it out.

Answer 12

I think I got it. Thanks but there is another question I'm going to need help with though. I'll post it in a bit if you want to look at it.