Question

will post in attachments

Answer 1

again, we have to compute the moles of sodium. So we have to do this computation:
\[n = \frac{{115}}{{23}} = ...?\]
since \(23\) is the atomic weight of sodium, pleas check the periodic table

Answer 2

please*

Answer 3

that would be 5

Answer 4

correct!

Answer 5

now, looking at the right side of the chemical rection, we note that number of moles of sodium chloride is equal to number of moles of sodium, so the quantity of produced sodium chloride is:
\[m = 5 \cdot 58.5 = ...?\]
\(58.5\) being the molecular weight of sodium chloride

Answer 6

292.5

Answer 7

so, what is the right option?

Answer 8

C

Answer 9

I am going to open up a new question

Answer 10

that's right!

Answer 11

ok!