Question

Need some geometry help

Answer 1

?

Answer 2

BC is tangent to circle A at B and to circle D at C. What is AD to the nearest tenth

Answer 3

I get the basic idea of it, but it would be really helpful is someone could walk me through it

Answer 4

Draw a line from A to C..Since BC is a tangent to circle A at B.it is perpendicular to the radius.So angle B is 90 degrees

Answer 5

let me know if this hint helps (see attached)

Answer 6

so we can use pythagorus theorem and find AC=
\[\sqrt{18^2+7^2} = 9.3\]

Answer 7

@jim_thompson5910 well. its slightly helpful. Im more looking for like a formula..

Answer 8

after that point, you use the pythagorean theorem

a^2 + b^2 = c^2

Answer 9

Ah, I was about to say that xD

Answer 10

a = 2
b = 18
c = unknown (length of AD)

Answer 11

So the square root of 324 +49 = 9.3?

Answer 12

not 49

Answer 13

focus on the triangle with legs of 2 and 18 (hypotenuse AD)

Answer 14

then 2^2 + x ^2 = 18^2??

Answer 15

more like

a^2 + b^2 = c^2
2^2 + 18^2 = c^2
c = ??

Answer 16

uhm i got 18.1107702762748333

Answer 17

`uhm i got 18.1107702762748333`

me too

Answer 18

So would that be the length of AD?

Answer 19

yes roughly 18.1 units

Answer 20

Thank you so much for showing me how to do this!

Answer 21

you're welcome