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Mathematics 14 Online
OpenStudy (anonymous):

Hellpp!!!

OpenStudy (anonymous):

OpenStudy (mathmate):

If mBC is real, then there is an infinite number of possible values. If mBC is integer (i.e. counting numbers), then you can work that out using the triangle inequality: The sum of any two sides of a triangle is greater than the third side, which I can make a corollary as: The sum of the two shorter sides of a triangle must be greater than the third side. But here you have another constraint, which is the sum of the two base angles must not be obtuse. |dw:1447070756509:dw|

OpenStudy (mathmate):

|dw:1447070800826:dw| From the diagram, we see that (x+y)<90 degrees is another constraint, this means that angle D must be obtuse. The Pythagoras theorem will express this inequality as: (mBC)^2>8^2+15^2 This provides the lower bound of mBC, while the triangle inequality gives the upper bound.

OpenStudy (anonymous):

then mBC>17; 7<mBC<23; 17<mBC<23 there are 6 values then is it true? but the answer key says it's 5

OpenStudy (anonymous):

@mathmate

OpenStudy (mathmate):

|dw:1447076838365:dw| :)

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