Question

hey i have an Algebra 2 question

Answer 1

bring it on

Answer 2

If a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will it take the football to hit the ground? Use the equation h = -16t2 + 36t + 4

Answer 3

h = -16t² + 36t + 4.
When h= 0, we have
0= -16t² + 36t + 4.
or 16t² − 36t − 4.=0
or 4t² − 9t − 1.=0
→t=[ − (−9)±√{(−9)²− 4×4×(− 1)}]/(2×4)
=[ 9 ±√{81+ 16}]/(8)
=[ 9±√{97}]/(8)
=2. 356 Seconds

Answer 4

it will hit the ground when h=0

Answer 5

from it we caluculate for t, with the help of the given equation/ you will get two values: one positive and another one negative, but time cannot be negative. so we will take the positive value

Answer 6

so h = -16t2 + 36t + 4= 0 is in standard form by converting it into a quadratic equation will give me my answer right ?

Answer 7

yeah right by putting h=0

Answer 8

k thanks one more thing i was trying to solve this but i didnt get the right answer

Answer 9

ok tell me

Answer 10

h = -16t2 + 36t + 4

Answer 11

can you use the equation button by the typing box pllllssssssssssss when explaining it makes it easier to comprehend

Answer 12

do you want me to solve it again? i mean the quadratic equation?

Answer 13

yes pls

Answer 14

we have
\[-16t^2+36t+4=0\] divide throughout by -4 and you have
\[4t^2-9t-1=0\]

Answer 15

now you solve this quadratic

Answer 16

no wait sorry

Answer 17

3x2 = 7x - 3

Answer 18

3^2=7x-3

Answer 19

\[3x^2=7x-3\]
implies
\[3x^2-7x+3=0\]

Answer 20

can u solve it though

Answer 21

yeah obviously. The general quadratic form is
\[ax^2+bx+c=0\]
where a, b,c are constants. and the solution is given by
\[x=(-b \pm \sqrt{b^2-4ac})/2a\]

Answer 22

mhmm

Answer 23

here a=3,b=-7,c=3 now plug in the values of a,b,c in the above formula

Answer 24

the answer is
\[x=(7\pm \sqrt{13})/6\]

Answer 25

@rebeccaxhawaii

Answer 26

howd you get 13 i got 43

Answer 27

\[(-7)^2-4*3*3=49-36=13\]

Answer 28

oh duh i forgot about the exponent thanks

Answer 29

n.p.

Answer 30

ok bye. @rebeccaxhawaii

Answer 31

WAIT

Answer 32

@jango_IN_DTOWN

Answer 33

ok.. but tell me fast

Answer 34

what did you get when solving the football player one

Answer 35

2.356secs approx

Answer 36

no no just in quadratic form what was the form

Answer 37

\[4t^2-9t-1=0\]

Answer 38

no the quadradic formula

Answer 39

Which part I cant get you

Answer 40

what is the equation in quadratic form

Answer 41

-16t² + 36t + 4.=0

Answer 42

no thats standard

Answer 43

h = -16t² + 36t + 4.
When h= 0, we have
0= -16t² + 36t + 4.
or 16t² − 36t − 4.=0
or 4t² − 9t − 1.=0
→t=[ − (−9)±√{(−9)²− 4×4×(− 1)}]/(2×4)
=[ 9 ±√{81+ 16}]/(8)
=[ 9±√{97}]/(8)
=2. 356 Seconds

Answer 44

no i just need the equation that is in standard form converted into quadratic form

Answer 45

ohkar ax^2+bx+c=0

Answer 46

that is standard i need it in quadratic

Answer 47

\[x=(-b \pm \sqrt{b^2-4ac})/2a\]

Answer 48

yes what is the equation when converted to that form

Answer 49

it is the solution of the standard form

Answer 50

no can you convert -16t² + 36t + 4=0 into quadratic form

Answer 51

ok divide throught y -4 and you have
\[4t^2-9t-1=0\]

Answer 52

\[t={-(-9)\pm \sqrt{(-9)^2-4*4*(-1)}}/(2*4)\]

Answer 53

why is it like that now ?

Answer 54

it was postitves before

Answer 55

here b=-9 which is negative

Answer 56

but why did it change ?

Answer 57

we divided by -4.. so a negative came

Answer 58

thank you so much @jango_IN_DTOWN