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OpenStudy (sphott51):
lnx - ln6 =lne6 ?
OpenStudy (freckles):
ln(x)-ln(6)=0
is the same as saying
ln(x)=ln(6)
for what number x is both sides the same
OpenStudy (freckles):
use what I said earlier or what satellite just said
that if ln(a)=ln(b) then a=b
OpenStudy (sphott51):
So x=6?
OpenStudy (freckles):
yes!
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OpenStudy (freckles):
ln(6)-ln(6) is totally zero
OpenStudy (freckles):
so x=6 definitely satisfies the equation
OpenStudy (sphott51):
Thanks!
Nnesha (nnesha):
let me see if i get 6 hmm
quotient rule\[\large\rm ln y - ln x = \ln \frac{ x }{ y}\]
so \[\ln \frac{x}{6}=0\]
take e both sides
\[e^{\ln}( \frac{ x }{ 6 })= e^0\]
e an ln cancels out
e^0 =1
\[\cancel{e^{\ln}}( \frac{ x }{ 6 })= e^0\]
\[\frac{ x }{ 6 }=1 \rightarrow x=6\]
OpenStudy (freckles):
on that one step where you have ln(x/6)=0
you can also recall that ln(1)=0
and then solve the equation x/6=1
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