The perimeter of a rectangle is less than 70 ft. The length of the rectangle is 5 ft longer than its width.
Write an equation representing the length (L = length) of the rectangle in terms of Its width.

L = _____________
b) The formula for perimeter of a rectangle is 2W + 2L = P
W is the width, L is the length, and P is the perimeter. Write an inequality using the formula (plug in the value of L found in part a, the value of P, and replace the equal sign with the appropriate inequality

@robtobey

Question

The perimeter of a rectangle is less than 70 ft. The length of the rectangle is 5 ft longer than its width.
Write an equation representing the length (L = length) of the rectangle in terms of Its width.

L = _____________
b) The formula for perimeter of a rectangle is 2W + 2L = P
W is the width, L is the length, and P is the perimeter. Write an inequality using the formula (plug in the value of L found in part a, the value of P, and replace the equal sign with the appropriate inequality

@robtobey

sloppycanada · Answer

Alright, so if the length of this thing is five more than the width, we can just write the simple equation - 

L = w +5

bossimbacon · Answer

@sloppycanada so what is the length?

lochana · Answer

put w+5 instead of L

bossimbacon · Answer

P= 2W + 2(w+5)? @lochana

lochana · Answer

good job

bossimbacon · Answer

how do we find the length from here do i subtract 5 from both sides

bossimbacon · Answer

and then divide 2 by both sides?

lochana · Answer

mm.. what kind of inequality are they asking?

lochana · Answer

P = 4W + 10

this is our answer so far

lochana · Answer

did you post the question completely?

bossimbacon · Answer

yes

bossimbacon · Answer

I have to go but thank yu for helping

lochana · Answer

I will see if I can find a solution:)

anonymous · Answer

From Mathematica v9:$$\text{Reduce}[ 2 (w+w+5)<70 ] $$w < 15
L  < 20

bossimbacon · Answer

@Vocaloid what is the length? of my question