I need help with this math question can someone please help me? If f(x)=2x^2-4x-3 and g(x)=(x-4)(x+4),find f(x)-g(x) Answers: 4x+13 x^2-4x+13 3X^2-4x+13 -4x^2-4x+13
f(x) - g(x) = 2x^2 - 4x - 3 - (x-4)(x + 4) first expand (x - 4)(x + 4) then subtract
How do I do that? @welshfella
(x + 4(x - 4) = x(x -4)+4(x - 4)
So is it like the foil method?? no? @welshfella
you can use the foil method if you prefer it
oh okay, so is the answer -4x^2-4x+13??
No tell me what you get for (x+4)(x-4)
okay is it this \[x^2-16+4x+4x\]?
kind of what i got when i foiled them... as you can see im not good in math at all @welshfella
nearly write but its +4x - 4x
okay i see
so the result is x^2 - 16 so now we have 2x^2 - 4x - 3 - (x^2 - 16) Note the parentheses around the x^2 - 16 Can you simplify this?
no i dont think so
you have to distribute the negative over the parentheses so -16 becomes -1*-16 = + 16
you completely lost me there 0_o
2x^2 - 4x - 3 - (x^2 - 16) = 2x^2 - 4x - 3 - x^2 + 16 now simplify like terms and you have the answzer
3x^2-4x+13??
bring like terms together to make it easier 2x^2 - x^2 - 4x -3 + 16
what is 2x^2 - x^2 ?
i know this sounds childish but suppose x^2 = an apple what we have here is 2 apples take away one apple
leaving one apple, right?
right
2 apples - 1 apple = 1 apple 2x^2 - 1 x^2 = ?
0
?
no x^2 = apple instead of an apple write x^2
wait so is it x^2-4x+13???
yes 2 x^2 - x^2 = x^2 we could write 1 x^2 but the 1 is usually left out 2x^2 and x^2 are like terms so you can subtract the
omg thank you so much for all of the help!! and for not giving up on me on this question @welshfella
yw
think of algebra as a kind of shorthand will help remember you can only simplify like terms 4x + x^2 cann ot be simplified because they are not like terms but 2x and 5x can - 2x + 5x = 7x
* 2x + 5x = 7x ( i didnt mean to put the negative there)
Thank you for that tip i will use it with any other math questions @welshfella
if you dont mind could you help me with more? @welshfella
sorry I have to go right now
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