Mathematics
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OpenStudy (anonymous):
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
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OpenStudy (anonymous):
@jojo12g
OpenStudy (anonymous):
@King.Void.
OpenStudy (anonymous):
@MrCoolGuy
Vocaloid (vocaloid):
rate of change = [f(8)-f(5)]/(8-5)
MsBrains (ms-brains):
Can you please snip the whole problem, and paste the link. So I can see the original and help better
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OpenStudy (anonymous):
OpenStudy (jojo12g):
@AlexandervonHumboldt2
OpenStudy (anonymous):
@Owlcoffee
OpenStudy (anonymous):
@Preetha
OpenStudy (jojo12g):
A because 0.01(2)4=0.08 @madison_taylor914
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MsBrains (ms-brains):
I'm not sure about this one... Sorry Madison.
OpenStudy (anonymous):
Which of the following options results in a graph that shows exponential decay?
f(x) = 0.6(2)^x
f(x) = 3(0.7)^x
f(x) = 0.4(1.6)^x
f(x) = 20(3)^x
OpenStudy (anonymous):
@Ms-Brains
OpenStudy (jojo12g):
A because 0.01(2)4=0.08 @madison_taylor914
OpenStudy (anonymous):
thats not what its asking @jojo12g
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OpenStudy (mrcoolguy):
im not sure on this one
OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
\[f(x)=0.1\times 2^x\] right?
OpenStudy (anonymous):
yes
OpenStudy (misty1212):
you need to compute \[f(8),f(3)\] and then take the slope \[\frac{f(8)-f(3)}{8-3}\]
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OpenStudy (misty1212):
the function is \[f(x)=0.01\times 2^x\] so \[f(8)=2.56\]
OpenStudy (misty1212):
\[f(3)=0.01\times 2^3=0.01\times 8=0.08\]
OpenStudy (anonymous):
so 2.48 final answer?
OpenStudy (misty1212):
no you still have to divide by 5
OpenStudy (anonymous):
.496
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OpenStudy (lochana):
yes. that's the answer
OpenStudy (anonymous):
thanks guys
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
OpenStudy (anonymous):
can you help me with one more? @misty1212