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Chemistry 13 Online
OpenStudy (summersnow8):

d

OpenStudy (caozeyuan):

\[\frac{ M _{solute} }{ M _{solution} }=\frac{ Mol _{solute}*Molar mass }{ Mol _{solute}*Molar mass +Mol_{solvent}*molar mass }\]

OpenStudy (caozeyuan):

assuming solvent is water

OpenStudy (caozeyuan):

ph wait, density is there!

OpenStudy (caozeyuan):

1M is 1mol per L, so if you have a liter of solution, you have () grams of solution with () mol of H2SO4 in it. This amount of H2SO4 would weight ()grams so the percent mass would be ()%. Fill in the blank

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