Check my answer please? Geometry proofs. Prove that opposite sides of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures.
This was my answer: A parallelogram typically has two sets of parallel lines. So, say we had a typical parallelogram (like this one that I drew for this question: http://prntscr.com/91djb0). Say we wanted to prove that side AB was congruent to side DC and that side AD was congruent to side BC. If we drew a line intersecting the figure, or a transversal in this case, it would look like this: http://prntscr.com/91dlmc That transversal will cut the parallelogram into two equal triangles. We will have triangle ABD, with angel ABD. We will also have triangle BDC, with angle BDC. As shown here, http://prntscr.com/91domn, angles ABD and BDC are alternate interior angles. By the alternate interior angles theorem, if a transversal intersects two parallel lines, then alternate interior angles are congruent. Therefore, angles ABD and BDC are congruent. Using these congruent alternate interior angles, we can use the Angle-Side-Angle Postulate to say that triangle ADB is congruent to triangle CBD. We can also say that side DC and side BA are congruent because they are corresponding sides of congruent triangles. Similarly, side AD will correspond to side CB. Therefore, we have now proven that opposite sides (AD and CB) are congruent on a parallelogram.
Before you can use ASA, you need another pair of congruent angles. But you can use the same reasoning/logic you used to prove that first pair of angles were congruent
That's all that's missing? I thought of that, but must've forgotten to put it in. Whoops Does it look find otherwise?
*fine
1st n 3rd pic not showing n everything @jim_thompson5910 said :)
@superdavesuper the links have a few extra characters at the end. Delete them and the links work fine
Yeah, the first and third won't show because of the symbols after the links in my essay.
So the other pair of congruent angles, according to the figures I'd drawn, would be DBC and ADB, correct?
That is correct.
Okay, so I've got everything now? I'm just trying to be a perfectionist on this question.
Well, I have everything by adding that in on my essay.
yes I think that was the only thing missing really. Other than that, it looks great
probably stating the "obvious" DB=BD as it is common. Otherwise u are all good :)
oh true, BD = BD or DB = DB by the reflexive property
Would that go at the end, after I've seemingly proven that?
it would go before ASA is used it's the "S" in ASA
Ah, okay. Thanks.
np
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