Question

help?


determine the discriminant. how many real solutions does it have?


3x^2 + 3 = 6x

Answer 1

what is this ^

Answer 2

We first need to put it in standered form
\[\huge~\rm~ax^2+bx+c=0\]

Answer 3

how do i do that

Answer 4

Start by subtracting 6x from both sides

Answer 5

\[\huge~\rm~3x^2 + 3 -6x= 6x -6x\]

Answer 6

3x^2+ -3x?

Answer 7

Nope the 6x becomes part of the equation
so you get
\[\huge~\rm~3x^2 -6x+3= 0\]

Answer 8

why does it though

Answer 9

What do you mean?

Answer 10

It always was we just made our equation equal 0 since its a quadratic expression we need it in standered for which is
\[\huge~\rm~ax^2+bx+c=0\]
from there we can name our abc values
\[\huge~\rm~3x^2 -6x+3= 0\]
a=3
b=-6
=c=3
Do you understand?

Answer 11

okay

Answer 12

@pooja195

Answer 13

y=3x2−6x+3
discriminant=\[\huge~\rm~b^2−4(a)(c)\]

Answer 14

discriminant=\[\huge~\rm~(-6)^2−4(3)(3)\]

Solve