Simplify i^{38} i -1 -i 1
Alright lets do this together.. first what do you think the answer is @Tatsurion
1 is my guess.
I believe you are right. You might want to confirm with someone else though :) Although, while I am here you can go to http://aihberliterally.wix.com/aihberliterally to book free math tutoring lessons.
Have a great day!
there is a simple way to figure those when you keep adding another i power a few times, you will notice a cycle every 4 terms repeat. so you can divide that large number by 4, and figure where in that 4 term sequence the anser is
i = i i^2 = -1 i^3 = i^2*i = -i i^4 = +1 then it repeats again, , like i^5 is just i^4 *i = i, same as i^1
So it is 1?
since that cycle repeats, you can take all the 4's out of 38, and the remainder will be the term in that 4 term sequence to use 4 goes into 38, 9 times, left over with 2 reaining, must be the same as i^2, the second of the 4 terms
-1
Oh! Now I get it.
or maybe think of it as, i^4 is just 1 factor out all the i^4 you can , those go to just multiplying by 1, left with the same answer
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