Question

Simplify the expression below:
Log((10^6)(X^2))

Answer 1

A 6+2log(x)
B 6x^2
C 12
D 12log(x)

Answer 2

familiar with the log rules ?

Answer 3

Not at all

Answer 4

Any type of mathematics are not my best subjects.

Answer 5

quotient rule\[\large\rm log_b x - \log_b y = \log_b \frac{ x }{ y}\]
to expand you can change division to subtraction
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition < ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]
that's all you need to know for this equation these are log rules

Answer 6

this topic is very easy they gave you 2 rules you just need to follow em

Answer 7

\[\huge\rm Log( 10^6 X^2 )\]which rule would you apply ??

Answer 8

\[\huge\rm Log( 10^6* X^2 )\]which rule would you apply ??
multiplication so change that to ??

Answer 9

I dont know, this is like a foreign language to me, Im sorry.

Answer 10

look at the rules i gave you try it !

Answer 11

here is an example \[\log (2 y) \] its `2 times y` multiplication so to expand i would apply product rule \[\rm \log(2)+\log(y)\]split it into two log

Answer 12

Log(10) and log(x)? or would the exponents come before the Log, 6Log(10) and 2Log(x) like this?

Answer 13

yes that's correct !

Answer 14

but wait what sign would be between both logs ?

Answer 15

product rule \[\large\rm log_b(x\color{reD}{*}y)= log_b x\color{ReD}{ +} \log_b y \]
addition < ----> multiplication
to expand change multiplication to addition

Answer 16

okay, so Log(10)+Log(x) is what it looks like then?

Answer 17

this is confusing, sorry about this.

Answer 18

yes don't forget the exponents \[\rm Log(10)^6+Log(x) ^2\] now apply power rule
move the exponents front of the logs

Answer 19

it's okay this is the easy subject :=))

Answer 20

i mean topic*

Answer 21

okay so 6Log(10)+2Log(x).

Answer 22

loks good!

Answer 23

looks*

Answer 24

Thank you so much, this helped alot.

Answer 25

np:=))