Question

9(3^3x+1)=1/9

Answer 1

what is the question ? Is we r here to solve the value of x @meghana12345

Answer 2

YUP

Answer 3

WE HAVE TO SOLVE FOR X

Answer 4

All right , then it's very easy . Do you need hint or the solution

Answer 5

ACTUALLY HINT

Answer 6

ok . Then at the very first , you have to separate all the other stuffs from x . then on the left hand side there will be only x . Can you do this ?

Answer 7

HOW ??

Answer 8

DONT GET IT

Answer 9

Just checking, is the equation

\[9(3^{x + 1}) = \frac{1}{9}\]

Answer 10

NO ITS 9(^3x+1)=1/9X

Answer 11

I WROTE THE QUESTION A BIT WRONG

Answer 12

I FORGOT TO PUT THE X

Answer 13

SORRY

Answer 14

so

\[9^{3x+1} = \frac{1}{9^x}\]

Answer 15

9(3^3x+1)=1/9X

Answer 16

THATS THE WRITE QUESTION

Answer 17

I am totally confused guys >< . What is the actual question ? I give up . Sorry

Answer 18

ok

\[9(3^{3x +1}) = \frac{1}{9^x}\]

Answer 19

YES

Answer 20

PLEASE TYPE FAST

Answer 21

ok... so to solve this you will need to rewrite the 9's as powers of 3... and without the freactions...

so you get

\[3^2(2^{3x + 1}) = (3^2)^{-x}\]

Answer 22

YES AFTER THAT

Answer 23

I DID TILL THERE

Answer 24

damn should read

\[3^2(3^{3x + 1}) = (3^2)^{-x}\]

now just apply the index laws for multiplicaion and power of a power

then you can solve

Answer 25

WHAAT??????

Answer 26

so on the left hand side use the law for multiplication of the same base

on th right you need power of a power

Answer 27

well you only wanted a hint...

Answer 28

PLEASE TELLME THE SOLUTION

Answer 29

PLEASE TYPE IT FAST

Answer 30

sorry I won't Open Study is about helping understanding

the laws

\[x^a \times x^b= x^{a + b}\]

this is for the left side

power of a power on the right

\[(x^a)^b = x^{a \times b}\]

Answer 31

once you have it simplified you can equate the powers and solve for x

Answer 32

i got the answer thanks

Answer 33

no please answer my other question