Question

What is the mass of 6.728 * 10^23 atoms Ag? answer in units of mol?

Answer 1

1st we find out the number of moles of Ag in 6.728 * 10^23 atoms of Ag.

\[moles=\frac{ No.OfAtoms }{ N_{a}}\]
N_{a} = Avagadro's number
\[moles=\frac{ 6.728 \times 10^{23} }{ 6.023 \times 10^{23} }\]\[moles=1.11\]

\[moles=\frac{ mass }{ MolarMass }\]\[1.11=\frac{ mass }{ 108 }\]
119.8=mass