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The sum of two consecutive integers is at least 46. What is the least possible pair of integers?
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divide 46 by 2, whatever you get is the smaller number
because it has to be at least 46
thanks
ur welcome :)
hold on
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the answers they gave me were: a. 21 and 23 b. 23 and 24 c. 22 and 23 d. 24 and 25
Its B. Pretty self evident, right?
why
Let the first integer be \(a\) and the second be \(b=a+1\) then $$ a+b=a+a+1\ge 46\\ 2a+1\ge 46\\ 2a\ge45\\ a\ge \cfrac{45}{2}=22.5\\ \implies a=23,b=24 $$ Make sense?
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