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Suppose the position of a function for a free falling object on a certain plane is given by s(t)=-11t^2+v0t+s0. A silver coin is dropped from the top of the building that is 1380 feet tall. a) find the instantaneous velocity of the coin at t=3 seconds. b) find the acceleration at t=3 seconds.
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Can you take the first and second derivative?
s'(t)=v(t)=-22t ?
v(3)=-22(3)=-66
not sure if i took the derivative right though
I think the position function is \[-16t^2 + V_0t + S_0\] You were given the initial position of the coin, but what was the initial velocity of the coin?
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S'(t) would be -32t + the constant of V But you didn't give V.
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