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Mathematics 6 Online
OpenStudy (anonymous):

Suppose the position of a function for a free falling object on a certain plane is given by s(t)=-11t^2+v0t+s0. A silver coin is dropped from the top of the building that is 1380 feet tall. a) find the instantaneous velocity of the coin at t=3 seconds. b) find the acceleration at t=3 seconds.

OpenStudy (anonymous):

Can you take the first and second derivative?

OpenStudy (anonymous):

s'(t)=v(t)=-22t ?

OpenStudy (anonymous):

v(3)=-22(3)=-66

OpenStudy (anonymous):

not sure if i took the derivative right though

OpenStudy (anonymous):

I think the position function is \[-16t^2 + V_0t + S_0\] You were given the initial position of the coin, but what was the initial velocity of the coin?

OpenStudy (anonymous):

S'(t) would be -32t + the constant of V But you didn't give V.

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