Question

Amy has a box containing 6 white, 4 red, and 8 black marbles. She picks a marble randomly. It is red. The second time, she picks a white marble. In the third attempt, Amy picks a white marble again. Amy has not replaced the marbles she picked.
The probability that the fourth marble Amy picks is black is ........?. If Amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is ........?.

Answer 1

@amistre64

Answer 2

this one seems to just be a longer drawn out version of the last

how many balls to start with?

Answer 3

15? well that's without replacement

Answer 4

18-3 = 15 good, and there are still 8 black eyes left to pick from right?

Answer 5

eyes? haha but yea so

P(black)=8/15

right?

Answer 6

marbles have cateyes :)

yes, the probability that the 4th pick is a black marble given the prior results is: 8 out of 15

Answer 7

what?! no way... haha wtf xD you serious???.... and alright i jus need the fraction, by the way..

Answer 8

now there are 14 marbles left ... how many left are red or black?

Answer 9

3 red, 7 black, 4 white

Answer 10

3+7= 10 that make a favored outcome

whats the probability of picking 10 out of 14 ?

Answer 11

so reduced its 5/7 ... right?

Answer 12

yep

Answer 13

sweet alright 3 more... one moment

Answer 14

thanks for the help by the way, i really appreciate it

Answer 15

yep, as long as youre participating in the solution process, im fine with it