Fred draws a card from a standard 52 card deck (no jokers.) Here are two possible outcomes: 1. The the card is a red face card (J, Q, or K of hearts or diamonds) 2. The card is a club. What is the probability that both 1 and 2 happen when he draws a card (the intersection)? What is the probability that at least one of 1 or 2 happens when he draws a card (union)? What is the probability 2 does not happen?
Hmm the first question is pretty straight forward, don't you think? :)
In drawing a single card, what are the odds that it is both black and red?
Isn't it 56? and there are 26 red cards?
52 sorry!
Hmm, this one should be really straight forward, still not getting it? :) If you draw `a single card`, how often will it be black AND red? Are you not familiar with a standard deck of cards? :o
No haha I'm not! I don't play cards and It can't be both the same color, right? So none!
Good :) It can't be both colors!
Union means OR, what are the odds that 1 OR 2 happens? So we'll figure out the odds of 1 happening, the odds of 2 happening, and then add those two things up.
13 clubs. 52 total cards. Odds of 2 happening? Odds of drawing a club? :)
is it 6 (red face cards) + 13? so 19? for the second one
and then the probability for the club not happening would be 3/4?
When we're looking for probability, we take that number and divide it by the entire sample space. So yes, 19 is the magic number we're looking for, 19 out of 52 possible cards meet the criteria for outcome 1 or 2. So our "Probability" is going to be 19/52.
Gotcha! I forgot that part. Thanks :) @zepdrix
Oh maybe you already understood that :) I see you put it correctly in the third part hehe
Yay good job \c:/ All looks good!
Thank you so much!! :) @zepdrix
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